the lowest term of (x^2-1)(x+2)(x^2-x-72)/(x-9)(x+1) is -
(a) (x+1)(x-2)(x+8)
(b) (x-1)(x-2)(x+8)
(c) (x-1)(x-2)(x+8)
(d) (x-1)(x+2)(x-8)
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Answered by
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Given : The expression (x^2-1)(x+2)(x^2-x-72)/(x-9)(x+1)
To find: The lowest term of (x^2-1)(x+2)(x^2-x-72)/(x-9)(x+1).
Solution:
- Now we have given the expression: (x^2-1)(x+2)(x^2-x-72)/(x-9)(x+1)
- Simplifying it, we get:
(x^2-1)(x+2)(x^2-x-72)/(x-9)(x+1)
(x - 1)(x + 1)(x + 2)(x^2 + 8x - 9x - 72) / (x - 9)(x + 1)
- Simplifying further, we get:
(x - 1)(x + 1)(x + 2)(x(x + 8) - 9(x + 8)) / (x - 9)(x + 1)
(x - 1)(x + 1)(x + 2)(x - 9)(x + 8) / (x - 9)(x + 1)
- Now cancelling the common terms from numerator and denominator, we get:
(x - 1)(x + 2)(x + 8)
Answer:
So the lowest term of (x^2-1)(x+2)(x^2-x-72)/(x-9)(x+1) is (x - 1)(x + 2)(x + 8)
Answered by
4
Answer:
lowest term of the given expression is
(x-1)(x+2)(x+8)
Step-by-step explanation:
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