Question

the lowest term of (x^2-1)(x+2)(x^2-x-72)/(x-9)(x+1) is -
(a) (x+1)(x-2)(x+8)
(b) (x-1)(x-2)(x+8)
(c) (x-1)(x-2)(x+8)
(d) (x-1)(x+2)(x-8)
I will mark the best answer as brainliest
Please give the answer

Answer 1

Given : The expression (x^2-1)(x+2)(x^2-x-72)/(x-9)(x+1)

To find: The lowest term of (x^2-1)(x+2)(x^2-x-72)/(x-9)(x+1).

Solution:

• Now we have given the expression:  (x^2-1)(x+2)(x^2-x-72)/(x-9)(x+1)

• Simplifying it, we get:

                  (x^2-1)(x+2)(x^2-x-72)/(x-9)(x+1)

                  (x - 1)(x + 1)(x + 2)(x^2 + 8x - 9x - 72) / (x - 9)(x + 1)

• Simplifying further, we get:

                  (x - 1)(x + 1)(x + 2)(x(x + 8) - 9(x + 8)) / (x - 9)(x + 1)

                  (x - 1)(x + 1)(x + 2)(x - 9)(x + 8) / (x - 9)(x + 1)

• Now cancelling the common terms from numerator and denominator, we get:

                  (x - 1)(x + 2)(x + 8)

Answer:

 So the lowest term of (x^2-1)(x+2)(x^2-x-72)/(x-9)(x+1) is (x - 1)(x + 2)(x + 8)

Answer 2

Answer:

lowest term of the given expression is

(x-1)(x+2)(x+8)

Step-by-step explanation:

hope it would be helpful to u....