Question

The LSA of a cuboid whose dimensions 15×12×10cm in sq. cms is​

Answer 1

Answer:

540 cm²

Step-by-step explanation:

The dimensions of the cuboid are given as 15cm, 12cm and 10cm.

Assuming that:

length = 15cm

breadth - 12 cm

height = 10 cm

LSA = Perimeter x height

LSA = 2(15 + 12) x 10

LSA = 540 cm²

Answer: The LSA is 540 cm²

Answer 2

Answer :-

• LSA of cuboid = 540 cm²

Given :-

• Length of cuboid = 15 cm
• Breadth of cuboid = 12 cm
• Height of cuboid = 10 cm

To Find :-

• LSA of cuboid = ?

Explanation :-

$\blue { \boxed { \bf \bigstar \; LSA \; of \; cuboid = 2H \; (L+B) \; \bigstar }}$

$\rm : \; \longrightarrow 2 \times 10 \; (15+12) \; \; cm^2$

$\rm : \; \longrightarrow 20 \; (27) \; \; cm^2$

$\rm : \; \longrightarrow 20 \times 27 \; \; cm^2$

$\green { \underline { \boxed { \bf : \; \longrightarrow 540 \; \; cm^2 \qquad \star }}}$

Hence, the LSA of the cuboid is 540 cm²

$\huge \text{\underline {\underline {More To Know}}}$

$\rm \odot \; TSA \; of \; cuboid = 2 \; (LB+BH+HL)$

$\rm \odot \; LSA \; of \; cuboid = 2H \; (L+B)$

$\rm \odot \; Volume \; of \; cuboid = L \times B \times H$

$\rm \odot \; TSA \; of \; cube = 6\; (L)^2$

$\rm \odot \; LSA \; of \; cube = 4 \; (L)^2$

$\rm \odot \; Volume \; of \; cube = (L)^3$