Biology, asked by Shivamd2521, 10 months ago

The lung cancer hazard rate (t) of a t-year-old male smoker is such that (t) = 0.027 + 0.00025(t 40)2, t 40 assuming that a 40-year-old male smoker survives all other hazards, what is the probability that he survives to (a) age 50 and (b) age 60 without contracting lung cancer?

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Answered by hiratayyab17
4

Answer:

The lung cancer hazard rate λ(t) of a t- year-old male smoker is such that ... t ≥ 40. Assuming that a 40-year-old male smoker survives all other hazards, The lung cancer hazard rate λ(t) of a t- year-old male smoker is such that λ(t) = .027 + .00025(t − 40)2 for t ≥ 40.

The lung cancer hazard rate of a t-year-old male smoker, λ(t) is such that λ(t)=0.027 + 0.00025 

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