The machine guns fire a bullet of mass 40g with a velocity 1200m/s . the man holding it , can exert a maximum force of 144N on the gun . How many bullets can he fire per second at the most ?
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Answered by
12
Explanation:
Given that, m=40g =0.04 kg
v=1200 m/s
and F=144 N
Let n be the number of bullets that can be fired per second.
The force exerted by man must balance the change in momentum of the bullets per second.
Hence, F = mnv
=>144 = 0.04×n×1200
=> 144 = 4×n×12
=>36 = n× 12
=> n = 3
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Answered by
4
Explanation :- force exerted by machine gun on man's hand in firing a bullet = change in momentum per second on a bullet or rate of range of momentum .
- =( 40/1000) × 1200 = 48N
- Force exerted by man on machine gun = 144N
Hence, number of bullets fired = 144/48
= 3 Answer
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