Question

The mad scientist has one solution that is 30% acid and another solution that is 18% acid. How much of 30% should he use to get 300 L of a solution that is 21% acid?

Answer 1

Given :

The mad scientist has one solution which is = 30% acidic

Another solution which is = 18% acidic

To find :

Quantity of 30% he should use to get 300L of a 21% acidic solution

Solution :

Let the amount of 30% which is to be mixed be T

Hence, the amount of 18% which is to be mixed will be = 300-T

According to the problem,

30T + 18(300-T) = 21(300)

=> 30T + 5400 - 18T = 6300

=> 12T + 5400 = 6300

=> 12T = 6300-5400

=> 12T = 900

Hence , T = 900/12

T = 75

Hence, quantity of 30% that is to be mixed is 75L.

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