The maesures of two angles of a quadrilateral are 90 degree and 60 degree.in the remaining two angles,one of them is half of to other. Find the angles
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0
let angle be x
other will be x/2
90+60+x+x/2 = 360
x+x/2 = 210
3x/2 = 210
x= 140
other angle is x/2 therefore is 70
other will be x/2
90+60+x+x/2 = 360
x+x/2 = 210
3x/2 = 210
x= 140
other angle is x/2 therefore is 70
Answered by
1
let remaining angle =X
2. remaining angle=x/2 as it is half of 1 angle
the total some of angle of quadilater=360
so,
90+60+x+x/2=360
150+x+x/2=360
X +X / 2=360 -150
taking lcm of x
so,
2x+x=420 as 210*2
3x=420
x=420/3
x =140
2angle =x/2
=140/ 2
=70°
hence
2. remaining angle=x/2 as it is half of 1 angle
the total some of angle of quadilater=360
so,
90+60+x+x/2=360
150+x+x/2=360
X +X / 2=360 -150
taking lcm of x
so,
2x+x=420 as 210*2
3x=420
x=420/3
x =140
2angle =x/2
=140/ 2
=70°
hence
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