Question

The magnetic field a distance 2cm from a long straight current carrying wire is 2.0×10-s5 T. The current in the wire is??

Answer 1

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Answer 2

✠Current in the wire = 2 A

$\texttt{\textsf{\huge{\underline{★explanation}:}}}$

✠The magnetic field is given by

$⇝B= \frac{\mu i}{2\pi r}$

⇝μo= 4π x 10⁻⁷ Tm/A

⇝i= current

⇝r=0.02 m

⇝B = magnetic field= 2 x 10⁻⁵ T

⇝2 x 10⁻⁵= (4π x 10⁻⁷)(i) / (2π*0.02)

⇝i=2 A