Question

The magnetic field at a perpendicular distance of 2 cm from an infinite straight current carying conductor
is 2 x 10"T. The current in the wire is
1) 0.1A
(2) 0.2 A
(3) GAA
(1) O.BA
1​

Answer 1

Explanation:

Answer and Explanation:

Magnetic field due to an infinite straight condun by

B=μ0I

2πr

Where

B is magnetic field

i is current through the conductor

r is the distance from the conductor

That gives

B1 -r2

B2 -r1

B2=r1B1

r2

We have

B1=4μT

r1=2cm=0.02m

r2=4cm

=

0.04

m

Plugging in the values

B2=0.02

0.04

6

That gives

B2=2μT

Thus magnetic field at a distance of 1 cm from the wire is

2μT

ï hope it help u ☺

Answer 2

Concept:

• Magnetic field strength
• Infinite current-carrying conductor
• The magnetic influence on moving electric charges, electric currents, and magnetic materials is described by a magnetic field, which is a vector field.
• A force perpendicular to the magnetic field and its own velocity acts on a moving charge in a magnetic field.

Given:

• Perpendicular distance d = 2cm = 0.02m
• Magnetic field B = 2*10^-6 T

Find:

• The current in the straight wire

Solution:

The magnetic field due to a straight current-carrying conductor is

B = μ₀I/2πd

2*10^-6 T = μ₀I/2π(0.02)

I = 2*10^-6 *0.04 π/ μ₀

I =  2*10^-6 *0.04 π/ 4π × 10-7

I = 0.2A

The current in the wire is 0.2A.

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