The magnetic field at centre of the coil having radius 2cm and current 100a and n=1 ,theta =90 degree??
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Number of turns on the circular coil, n = 100
Radius of each turn, r = 8.0 cm = 0.08 m
Current flowing in the coil, I = 0.4 A
Magnitude of magnetic field at the centre of circular coil is given as:
B = (μ0/ 4π) ((2 π n l) /r)
Where μ0 = Permeability of free space = 4π × 10–7 T m A–1
Therefore B = (4π × 10–7 x 100 x 0.40)/ (2 x 8 x10-2)
B = 3.14 x 10-4 T
Explanation:
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