The magnetic field at the centre o of the arc is
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To find this magnetic field we can use the formula for magnetic field at the center of a current carrying coil with N turns:
B=( mu zero)NI/2R.
(mu zero)= magnetic permeability of space=4pix10^-7 Tm/A
I current in ampere
R radius of arc in meter
The number of turns ,in our problem will be N=(theta/2pi), because angle 2pi corresponds to one turn.
Therefore , B=( mu zero)I(theta)/(4pi R)
Magnetic field B is vector . It’s direction is normal to the plane of arc pointing away from us if current is clock wise or towards us if current is anti clock wise.
B=( mu zero)NI/2R.
(mu zero)= magnetic permeability of space=4pix10^-7 Tm/A
I current in ampere
R radius of arc in meter
The number of turns ,in our problem will be N=(theta/2pi), because angle 2pi corresponds to one turn.
Therefore , B=( mu zero)I(theta)/(4pi R)
Magnetic field B is vector . It’s direction is normal to the plane of arc pointing away from us if current is clock wise or towards us if current is anti clock wise.
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