The magnetic field at the centre of a circular coil is 5 μT. How will the magnetic field change if current as well as number of turns in the coil are doubled? a)10 μT b)20 μT c)15 μT d)5 μ T
Answers
Answer:
it will the magnetic field at the centre at control is 5t it will get magnetic field change is current as well as number of turns in the coil doubled if 10 it is it is right 22 it is wrong in 1885 thank you please
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Answer:
At the center of a current carrying coil, the magnetic field intensity is directly proportional to the current and inversely proportional to the radius of the coil. So, if the current is doubled and radius is halved, then the value of B increases by 4 times the initial value.
Explanation:
The magnetic field at the centre of a circular coil carrying current is
The magnetic field at the centre of a circular coil carrying current isB = mu(0) n I / (2r)
The magnetic field at the centre of a circular coil carrying current isB = mu(0) n I / (2r)Where mu(0) is the permeability of free space, n is the number of turns in the coil, I the current in the coil and r it's radius.
The magnetic field at the centre of a circular coil carrying current isB = mu(0) n I / (2r)Where mu(0) is the permeability of free space, n is the number of turns in the coil, I the current in the coil and r it's radius.It should be easy enough to get the answer you want.
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