The magnetic field at the centre of a the circular coil is 5 μT. How will the magnetic field change if current as well as number of turns in the coil are doubled? a)10 μT b)20 μT c)15 μT d)5 μ T
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0
Answer:
The magnetic field on the axis of the loop is B
z
=
4π
μ
0
(z
2
+R
2
)
3/2
2πR
2
I
Field at centre is B
c
=
4π
μ
0
R
3
2πR
2
I
thus,
B
z
B
c
=
R
3
(z
2
+R
2
)
3/2
=
3
3
(4
2
+3
2
)
3/2
=
27
125
or B
c
=
27
125
×54=250μT as (B
z
=54μT)
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Answer:
: At the center of a current carrying coil, the magnetic field intensity is directly proportional to the current and inversely proportional to the radius of the coil. So, if the current is doubled and radius is halved, then the value of B increases by 4 times the initial value
Explanation:
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