Question

The magnetic field at the centre of the circular coil carrying current of 4 A

Answer 1

Answer:

B = 4μ0/2R

Explanation:

The magnetic field at the centre of the circular coil carrying current,

B = (μ)I/2R

B = 4μ/2R

where μ = permeability of medium

R = radius of circular coil

Hole it helps.

Answer 2

Concept:

• The magnetic field of a circular coil
• Calculating the value of a magnetic field in a current-carrying circular coil

Given:

• Current I = 4 A
• Coil is circular
• The magnetic field at the centre
• The radius of the circular loop = R

Find:

• The value of the magnetic field at the centre of a current-carrying circular coil

Solution:

μ₀ = 4π × 10⁻⁷

Let the radius of the circular loop be R

Magnetic field B in a circular coil = 4μ₀/2R

The magnetic field at the centre of a circular coil is 4μ₀/2R.

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