Question

The magnetic field B due to a current- carrying circular loop of radius 12cm at its center is 0.50 xx (10^-4) T. Find the magnetic field due to this loop at a point on the axis at a distance of 5.0 cm from the centre.

Answer 1

Answer:

$\frac{uoi}{2r} = 5 \times {10}^{ - 5} - - - 1eq \\ \frac{uoi {r}^{2} }{2 {( {r}^{2} + {x}^{2} ) }^{ \frac{3}{2} } } = mx - - - - 2eq \\ on \: deviding \: both \: the \: eq \: \\ we \: get \: \: mx \: = 4 \times {10}^{ - 5}$

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