The magnetic field existing in a region is given by [vector B= B not (1+x/l)*k cap ]. A square loop of edge 'l' and carrying a current 'i', is placed with its edge parallel to the x-y axes. Find the magnitude of the net magnetic force experienced by the loop:
correct answer: [i*Bnot*l]
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Answered by
11
we know, Bx = Bo(1+x/l)k, and Bx+l = Bo(1- (x+l)/l)k. Now, Fx = i (l x Bx),
this implies, Fx = ilBxo (j x k) = ilBxoi = ilBo (1+x/l)i. Similarly, Fx+o = -ilBo (1+(x+l)/l)i.
Therefore, the net force = Fx + Fx+o = ilBo(1+x/l)i – ilBo (1+(x+l)/l)i.
Hence, the magnitude of the net force is ilBo.
Answered by
7
we know, Bx = Bo(1+x/l)k, and Bx+l = Bo(1- (x+l)/l)k. Now, Fx = i (l x Bx),
this implies, Fx = ilBxo (j x k) = ilBxoi = ilBo (1+x/l)i. Similarly, Fx+o = -ilBo (1+(x+l)/l)i.
Therefore, the net force = Fx + Fx+o = ilBo(1+x/l)i – ilBo (1+(x+l)/l)i.
Hence, the magnitude of the net force is ilBo.
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