The magnetic field of a distance of 2cm from
the axis of straigh conductor carring
current is 12mt. The current in the
conductor is
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Answer:
I = 1200A
Explanation:
B = μi/2πR
12 × 10⁻³ = (4π × 10⁻⁷)i/2π(2 × 10⁻²)
i.e i = 1200 ampere
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