Question

The magnetic field of magnitude 2.1 t is acting vertically on the laboratory chamber. a proton having kinetic energy 3.7 mev enters horizontally in the chamber. how much deflection force act on proton and in what direction.

Answer 1

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Show that the relativistic expression for the kinetic energy of a particle (Eq. 1.2) reduces to ... momentum the proton can have is Pc = 448.5 MeV. ... section for the collision is 3.7 × 10.