The magnetic flux linked for an iron bar of 0.2 cm2 within a magnetic field of 1.2 wb/m2 is?
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Answer:
μ
0
=4π×10
−7
Wb/Am
H=1200Am
−1
χ=599
The permeability of the iron rod is given by
μ=μ
0
(1+χ)
μ=4×3.14×10
−7
(1+599)=7.536×10
−4
H/m
The magnetic field produced is,
B=μH
B=7.536×10
−4
×1200=0.904T
The magnetic flux per unit area is 0.904×10
−5
Wb
Explanation:
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