Question

The magnetic flux linked with a coil changes by 2×10-2Wb when the current changes by 0.01A. The self inductance of the coil is_______.

Answer 1

Answer:

Self inductance of the coil, L = 2 Henry

Explanation:

It is given that,

Magnetic flux linked with the coil, $\phi=2\times 10^{-2}\ Wb$

Change in current, $\Delta I=0.01\ A$

The relation between the magnetic flux and the self inductance is given by :

$\phi=L\times \Delta I$

$L=\dfrac{\phi}{\Delta I}$

$L=\dfrac{2\times 10^{-2}}{0.01}$

L = 2 Henry

So, the self inductance of the coil is 2 Henry. Hence, this is the required solution.

Answer 2

Faraday's Principle of Electromagnetic Induction states that the emf induced in a loop due by a changing magnetic flux is equal to the rate of change of the magnetic flux threading the loop. The magnetic flux threading a coil of wire can be changed by moving a bar magnet in and out of the coil.