Question

The magnetic flux near the axis inside the air core solenoid carrying current I is π/2 micro wb . length of solenoid is 60 cm . what will be its magnetic moment ?​

Answer 1

The magnetic moment will be 0.75 Am²

Explanation :

Given,

flux = π/2 x 10⁻⁶ wb

Length = 60 cm = 0.6 m

we know that, the magnetic flux is given by,

Φ = BA

=> A = Φ/B

Also,

B = μ₀NI/L

=> A = ΦL/ μ₀NI

we know that , magnetic moment is given as,

M = NIA = NI(ΦL/ μ₀NI)

=> M = ΦL/ μ₀ = π/2 x 10⁻⁶ x 0.6/4π x 10⁻⁷

= 0.75 Am²

Hence The magnetic moment will be 0.75 Am²