Physics, asked by taha1157, 1 year ago

The magnetic flux through a loop of resistance 0.1Ω is varying according to the relation Φ = 6t² + 7t + 1 where Φ is in milliweber and 't' is in second. What is the e.m.f. induced in the loop at t = 1 s and the magnitude of the current?
(Ans: 19mv, 190mA)

Answers

Answered by Anonymous
5
hey mate
here's the solution
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Answered by amitnrw
3

Answer:

19 mV

190 mA

Explanation:

The magnetic flux through a loop of resistance 0.1Ω is varying according to the relation Φ = 6t² + 7t + 1 where Φ is in milliweber and 't' is in second. What is the e.m.f. induced in the loop at t = 1 s and the magnitude of the current?

EMF induced = dΦ/dt

= d(6t² + 7t + 1)/dt

= 12t + 7

at t = 1  , 12 * 1 + 7 = 19

19 mV  ( as Φ is in milliweber)

Current = Emf induced/ Resistance

=> Current =  19 mV/0.1 = 190 mA

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