Question

The magnetic force on a current carrying wire placed in uniform magnetic field if the wire isoriented perpendicular to magnetic field, is ................. [ ]a) 0
b) ILBc) 2ILB
d) ILB/2

Answer 1

Answer:

ILB is the answer of this question

Answer 2

The magnetic force on a current carrying wire placed in uniform magnetic field if the wire is oriented perpendicular to magnetic field, is b) ILB.

Explanation:

Current passing through wire be I

Length of the wire be L

Magnetic field produced by the wire is B

Magnetic force is given by the formula:

$\bold{F=I L B \sin \theta}$

Since, the wire and the magnetic field is perpendicular.

$\theta=90^{\circ}$

$\because \ \sin 90^{\circ} = 1$

Now, the magnetic force becomes,

$\bold{\therefore F=I L B}$