Question

the magnetic force on a current carrying wire placed in uniform magnetic field if the wire is oriented perpendicular to the magnetic field is

Answer 1

Magnetic  force on a current carrying conductor placed in a uniform magnetic field can be given by equation
F=ILB

Let θ be the angle between direction of current and magnetic field, then force acting on the current carrying wire is 
F=ILB sinθ ( at any angle)

If the wire is oriented perpendicular to the magnetic field then θ=90°
F=ILBsin90°
F=ILB [∵ sin90°=1]

Answer 2

Answer:

The answer is obviously 0

Explanation:

The magnetic force on a current carrying wire placed in uniform magnetic field if the wire is oriented perpendicular to the magnetic field is 0 because no force is gonna act on wire as the magnetic field lines and wire is in the same direction