Question

The magnetic force on an electric charge of 10 x 10-2C moving with velocity 5 ms-1 normal to the uniform

magnetic field of 10 T is …?​

Answer 1

Answer:

ANSWER

The force acting on a charged particle moving in a magnetic field

B

is given by

F

=q(

v

×

B

)

⟹

∣

∣

∣

∣

F

∣

∣

∣

∣

=1.6×10

−19

×10

5

×2N

=3.2×10

−14

N

Explanation:

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Answer 2

Answer:

we need 10T high magnetic field in our experiment, is there any magnet that i can apply to this field??

Explanation:

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