the magnetic induction field due to a magnetic south pole of strength 50Am at a point in air 10cm away from the pole in weber is
Answers
Answered by
1
Explanation:
Length of magnet = 10 cm = 10 × 10
−2
m,
r = 15 × 10
−2
m
op=
225−25
=
200
cm
Since , at the neutral point , magnetic field due to the magnet is equal toB
H
B
H
=
4π
μ
O
⋅
(OP
2
+AO
2
)
3/2
M
0.4×10
−4
=10
−7
×
(200×10
−4
+25×10
−4
)
3/2
M
10
−7
0.4×10
−4
×(225×10
−4
)
3/2
=M
0.4×10
−6
225
3/2
=M
M=1.35A−m
Answered by
0
Answer:
B = μni/2r
= 25 * 10 ⁻⁶
Explanation:
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