Question

The magnetic moment of a transition metal ion is found to be 5.92 bm. The number of unpaired electrons present in it is

Answer 1

5. ( shortcut . its the first no. )

or.

• bm=
• $\sqrtx(x + 2)$
• x = is no. of unpaired electron

Answer 2

The number of unpaired electrons present in it are 5

Explanation:

Formula used for spin only magnetic moment :

$\mu=\sqrt{n(n+2)}$

where,

$\mu$ = magnetic moment

n = number of unpaired electrons

Now put all the given values in the above formula, we get the magnetic moment.

$5.92=\sqrt{n(n+2)}$

$35.05=n(n+2)$

$n=5$

The number of unpaired electrons present are 5

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