Chemistry, asked by naveen64751, 9 months ago

The magnetic moment of an octahedral co(ll) complex is close to 4.0MB.The d electronic configuration of co(ll) in the complex is

Answers

Answered by alaihakhan321
1

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Answered by SmritiSami
3

The d electronic configuration of Co(ll) in the complex is t2g⁵ and eg², as Co2+ has 3 unpaired electrons.

Given:-

Magnetic moment (m) = 4MB

To Find:-

The d electronic configuration of Co(ll) in the complex.

Solution:-

To find out the d electronic configuration of Co(ll) in the complex, we have to follow these simple steps which includes.

Now,

Magnetic moment (m) = 4MB

Electronic configuration of Co (27) = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁷

Electronic configuration of Co²+ = 1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁷

Co²+ = 4s⁰ 3d⁷

So, Co(II) has three unpaired electron in its excited state when paired with weak field ligand.

And the d electronic configuration of Co(II) is t2g⁵ and eg².

Hence, The d electronic configuration of Co(ll) in the complex is t2g⁵ and eg², as Co2+ has 3 unpaired electrons.

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