The magnetic quantum number for the valence electron of rubidium is
Answers
Answered by
2
Answer:
Given, atomic number of Rb, Z = 37 Thus, its electronic configuration is [Kr]5s1. Since, the last electron or valence electron enter in 5s subshell. So, the quantum numbers are n = 5, l = 0, (for s-orbital) m = 0(∵ m = + l to -l), s = + 1/2 or -1 / 2.
Answered by
0
Explanation:
follow me i will follow back, u and like my all answers
Attachments:
Similar questions