Question

The magnetic susceptibility of bismuth is -2.1 x 10-6

. Calculate its relative permeability.​

Answer 1

Answer:

B = µ * H , where µ is the permeability, M = χ * H , where χ is the magnetic susceptibility (check Curie's law calculator), B = µ₀ * (H + M) , where µ₀ = 4 * π * 10^(-7) H/m is the magnetic permeability of free space. The unit H is called "henry" and it is an unit of inductance (check solenoid inductance calculator).

Answer 2

Given: Magnetic susceptibility of bismuth is -2.1*10^-6

To find: Relative permeability of bismuth

Explanation: Let magnetic susceptibility be x= -2.1* 10^-6( magnetic susceptibility of diamagnetic material is negative).

Now, formula for calculating relative permeability is u= 1+x where u is relative permeability and x is magnetic susceptibility of the material which in this case is bismuth.

Therefore, u= 1+ (-2.1*10^-6)

= 1 - 0.0000021

= 0.9999979

Therefore, the relative permeability of bismuth is 0.9999979