The magnetic susceptibility of bismuth is -2.1 x 10-6
. Calculate its relative permeability.
Answers
Answer:
B = µ * H , where µ is the permeability, M = χ * H , where χ is the magnetic susceptibility (check Curie's law calculator), B = µ₀ * (H + M) , where µ₀ = 4 * π * 10^(-7) H/m is the magnetic permeability of free space. The unit H is called "henry" and it is an unit of inductance (check solenoid inductance calculator).
Given: Magnetic susceptibility of bismuth is -2.1*10^-6
To find: Relative permeability of bismuth
Explanation: Let magnetic susceptibility be x= -2.1* 10^-6( magnetic susceptibility of diamagnetic material is negative).
Now, formula for calculating relative permeability is u= 1+x where u is relative permeability and x is magnetic susceptibility of the material which in this case is bismuth.
Therefore, u= 1+ (-2.1*10^-6)
= 1 - 0.0000021
= 0.9999979
Therefore, the relative permeability of bismuth is 0.9999979