The magnetized wire of magnetic moment M is bent into an arc of a circle that subtends an angle of 60 at the center. The equivalent magnetic moment is ?
Answers
Answered by
64
Hey mate,
◆ Answer- 3M/π
◆ Explanation-
# Given-
θ = 60°
# Solution-
Resultant magnetic moment of a wire bent into arc of circle subtending angle θ at centre is given by-
M' = 2Msin(θ/2) / θ
Substituting values-
M' = 2Msin30 / π/3
M' = 3×2×M×1/2 / π
M' = 3M/π
Hence, equivalent magnetic moment of a wire will be 3M/π.
Hope that is all...
◆ Answer- 3M/π
◆ Explanation-
# Given-
θ = 60°
# Solution-
Resultant magnetic moment of a wire bent into arc of circle subtending angle θ at centre is given by-
M' = 2Msin(θ/2) / θ
Substituting values-
M' = 2Msin30 / π/3
M' = 3×2×M×1/2 / π
M' = 3M/π
Hence, equivalent magnetic moment of a wire will be 3M/π.
Hope that is all...
Answered by
15
Answer:
Explanation: No need of hefty formulas
Just remember this M=m L
Now, in this case, using R∅=L
R= 3L/π
Now, M'= m R
Substitution, we get M'=3M/π
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