Question

The magnification of a virtual image formed by a concave mirror is found to be 1.5. If the object is placed at a distance of 15cm from the pole of the mirror ,then the distance of the image from the pole of the mirror is:
a) 15cm b) 2.25cm c)150cm d) 22.5cm

Answer 1

A car moves for half of its total travel time with a speed 80km/HR and for next half of the time at 40km/HR. the total distance covered is 60km. find the average speed of the car

Answer 2

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d) 22.5cm

${\huge{\boxed{\mathcal{\red{Explanation}}}}}$

It is given that magnification of this virtual image formed by concave mirror is 1.5.

Magnification of an object is the ratio of height of its image to height of object.

Magnification is also defined as the ratio of image distance to object distance. Mathematically it can be defined as

$\frac{h_i}{h_o} or \frac{v}{u}$

$\frac{h_i}{h_o} = \frac{v}{u} \: always$

Where :

$h_i = height \: of \: image \\ h_o = height \: of \: object \\ v = image \: distance \\ u = object \: distance$

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Now coming to question:

Magnification = 1.5

Object distance = u = 15cm.

Now as we know

$magnification \: (m) = \frac{v}{u}$

$1.5 = \frac{v}{15}$

$v = 1.5 \times 15$

$v = 22.5cm$

Thus the distance of image from pole of mirror is 22.5cm.

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