Question

The magnification of a virtual image of an object placed at a distance 0.2m from a lens is 0.5.The lens will be. 1,concave lens of focal length 0.1m. 2. concave lens of focal length 0.2m. 3.convex lens of focal length 0.1m. 4. convex lens of focal length 0.2m​

Answer 1

Answer:

From lens formula

=

1v−

u

1

f

1

v

u

−1=

f

u

v

u

=

f

u+f

u

v

=

u+f

f

For a convex lens f = 0.12m and m=3 then find u

So , 3=

0.12+u

0.12

0.36+3u=0.12

u=−0.08m

Answer 2

Answer:

Here is your answer mate