The magnifying power of an astronomical telescope in the normal adjustment position is 100. The distance between the objective and the eye-piece is 101 cm. Calculate the focal lengths of the objective and of the eyepiece.
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Answered by
12
it is given that, distance between the objective and the eye-piece , = 101 cm.....(1)
magnification, m = = 100
or, ......(2)
from equations (1) and (2),
or,
and = 100 = 100
hence, focal length of objective = 100cm
focal length of eyepiece = 1cm
magnification, m = = 100
or, ......(2)
from equations (1) and (2),
or,
and = 100 = 100
hence, focal length of objective = 100cm
focal length of eyepiece = 1cm
Answered by
0
Answer:
100 cm and 1 cm respectively
Explanation:
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