Question

The magnifying power of the astronomical telescope for normal adjustment is 50. The focal length of the eye piece is 2cm. The required length of the telescope for normal adjustment is

Answer 1

Length = focal length of eyepiece + focal length of objective lens
We know magnifying power in normal adjustment = focal length of objective lens divided by focal length of eye piece
Focal length of objective lens= 50 * 2= 100
Length= 100+2

Answer 2

Length = focal length of eyepiece + focal length of objective lens

We know magnifying power in normal adjustment = focal length of objective lens divided by focal length of eye piece

Focal length of objective lens= 50 * 2= 100

Length= 100+2

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