the magnitude of 1/4πε0 is
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Answer:
Since the unit of force is the Newton (N), the unit of electric field is N/C, where C is the unit of electric charge, the Coulomb. k = 1/4πϵ0 = 9×109Nm2/C2 = 9×109kgm3/C2s2.
Explanation:
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Answer:
The value of the electrostatic constant 1/4π∈₀ is 9 × 10⁹ Nm²C⁻².
Explanation:
Given,
1/4π∈₀
To find,
The value of 1/4π∈₀
Concept,
- As 1/4π∈₀ is equal to 'k' which is known as the electrostatic constant.
- It has units of Nm²C⁻².
Calculation,
Here in 1/4π∈₀, the value of 'π' can be taken as 3.14, and the electric permittivity of free space '∈₀' has a value of 8.85 × 10⁻¹² F/m(farad per meter).
So, we plug in all the values to find 'k'
k = 1/4 × 3.14 × 8.85 × 10⁻¹²F/m
k = 9 × 10⁹ Nm²C⁻² (As 1F = N⁻¹m⁻¹C²)
Therefore, the value of the electrostatic constant 1/4π∈₀ is 9 × 10⁹ Nm²C⁻².
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