Question

The magnitude of a given vector with end pointts (4, -4 , 0) and (-2 , -2, 0) must be

Answer 1

Answer:

√40 or 2√10

Explanation:

given,

• first point=(4,-4,0). therefore, it's position coordinate will be 4i -4j
• second point=(-2,-2,0) and it's position coordinate will be -2i -2j
• Their displacement vector will be (x2-x1)i + (y2-y1)j + (z2-z1)k = (-2-4)i + (-2-(-4))j = -6i + 2j
• magnitude of the displacement vector will be
• $\sqrt{ {x}^{2} + {y}^{2} + {z}^{2} } \\ = \sqrt{ { - 6}^{2} + {2}^{2} } \\ = \sqrt{36 + 4} \\ = \sqrt{40} \\ = 2 \sqrt{10}$

hope it helps....!!!