Question

The magnitude of a vector is 25m, if its y component is 12.5m. What angle does this vector make with x axis?

Answer 1

Answer:

30

Explanation:

let the vector be Z and it makes angle A with x-axis

its y component will be

ZsinA

given that the magnitude of vector Z is 25

and its y component = 12.5

25sinA = 12.5

sinA = 12.5/25

sin A = 1/2

sinA = sin30

A = 30

Answer 2

$\huge\underline\mathfrak\red{ANSWER}$

[tex]let \: the \: angle \: between \: the \: vector \\ and \: y \: axis \: be \: \alpha \: than \: its \: component \\ on \: y \: axis \: is \: given \: as... \\ \\ |a| \cos \alpha \\ \\ where \: |a| \: is \: the \: magnitude \: of \: the \: \\ vector.... \\ \\ acc \: to \: the \: question \\ \\ | a| = 25m \\ \\ |a| \cos \alpha = 12.5m \\ \\ \cos \alpha = \frac{12.5}{25 } \\ \\ \cos \alpha = \frac{1}{2} \\ \\ \alpha = \frac{\pi}{3} \\ \\ as \: u \: dont \: mention \: the \: quadrant \\ so \: i \: consider \: first \: quadrant \\ \\ \alpha + \beta = \frac{\pi}{2} \\ \\ where \: \beta \: is \: the \: angle \: formed \: by \\ \: x \: axis.... \\ \\ \frac{\pi}{3} + \beta = \frac{\pi}{2} \\ \\ \beta = \frac{\pi}{2} - \frac{\pi}{3} \\ \\ \beta = \frac{\pi}{6} .

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