Question

the magnitude of acceleration of particle executing SHM at the position of maximum displacemment is?​

Answer 1

Answer:

The acceleration of the particle executing S.H.M is, a=−ω2y. Hence ∣amax∣=ω2a. i.e., acceleration will be maximum.

Answer 2

Answer:

Explanation:As we know that in SHM is

a = W².x where x is the displacement or distance from mean position

So Maximum displacement from mean position is equal to Amplitude represent by A

So Maximum a is equal to

a = W²A