The magnitude of an orbital angular momentum
vector of an electron is V into how many
components will the vector split if an external field
is applied to it?
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Answer:
Explanation:
The orbital angular momentum is given by
l(l+1)
×h/2π
In the question it is given to be
6
×h/2π
so, it means
l(l+1)
=
6
l = 2
The possible values of magnetic quantum number for l=2 will be
m
l
=−2,−1,0,1,2
So, the vector can split into five components in the presence of external magnetic field.
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