Question

The magnitude of both scalar and vector products of two vectors are 48 root 3 and 144

Answer 1

Scalar product of 2 vectors is given by :

A.B = ABcosθ = 48√3

Vector product of 2 vectors is given by :

A x B = ABsinθ = 144

or, Dividing the two equations we get, tanθ = √3

or, θ = 60°

Since there's nothing mentioned in the question what to find out so we can terminate it here after finding the angle between the two factors.

Answer 2

HELLO DEAR,

GIVEN THAT:-

scalar product = 48√3 = A.B.cosØ

Vector product = 144 = A.BsinØ

and hope we know $\bold{\large{tan\theta = \frac{VECTOR\;\; PRODUCT}{SCALAR\;\; PRODUCT}}}$

So, $\bold{\large{tan\theta = \frac{144}{48\sqrt{3}}}}$

$\bold{\large{tan\theta = \sqrt{3}}}$

Hence, $\bold{\boxed{\theta = 60\degree}}$

I HOPE ITS HELP YOU DEAR,
THANKS