Question

The magnitude of change in velocity of a particle having speed v is v during a time interval t while moving in

a uniform circular motion. The magnitude of centripetal force on the particle is proportional to​

Answer 1

Answer:

When a particle completes half circle velocity change’s from v to -v ( directions are opposite to each other) hence change in momentum when particle completes half circle △p = mv -(-mv) = 2mv

Time taken I completing the half circle = △t = πr/v

Average force

F = △p/△t

={2mv}/(πr/v)

= {(2mv²)/πr}