Question

The magnitude of current density in a copper wire is 500 A/cm². If the number of free electrons per cm of copper is 8.47x1022 calculate the drift velocity of the electrons through the copper wire
(charge on an e = 1.6x10-19 C)​

Answer 1

Answer:

Drift velocity of electrons in the wire is

$v_d = 3.7 \times 10^{-4} m/s$

Explanation:

As we know that current density is defined as

$j = nev_d$

here we know

n = number of free electrons per unit volume

$n = 8.47 \times 10^{22} per cm^3$

$e = 1.6 \times 10^{-19} C$

$j = 500 A/cm^2$

$j = 500 \times 10^4 A/m^2$

now by above formula

$500 \times 10^4 = (8.47 \times 10^{28})(1.6 \times 10^{-19} v_d$

$v_d = 3.7 \times 10^{-4} m/s$

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Topic : current density

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