Question

the magnitude of dot and Cross product of two vector is 6√3 and 6 respectively, find the angle between the vector​

Answer 1

Explanation:

Let take A ,B as vectors

So, Dot product: A.B = AB COS(@) = 6√3

Cross product: A×B = AB SIN (@) = 6

Divide 2 by 1, we get

TAN(@) = 1/ √3

Therefore, @= 30°

HOPE YOU UNDERSTAND...