the magnitude of dot and cross product of two vectors is 6underroot3 and 6 respectively. find the angle between the vectors
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Let θ be the angle between two vectors a & b then
The scalar product is given as
a.b=abcosθ =6√ 3 .....(1)
The magnitude of Vector product is given as
a*b=absinθ=6......(2)
The magnitude of Vector product is given as
Dividing (2) by (1) as follows
absinθ/abcosθ=6 √ 3/6
tanθ=1/ √ 3
θ=tan inverse 1/ √ 3
θ=30∘
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