Physics, asked by vaibhavsingh17p1mflo, 11 months ago

The magnitude of electric field in a region varies with the distance 'r' as E=10r+5, then By by how much does the potential increase in moving from point at r=1 meter to a point at r=10 meter?

Answers

Answered by wajahatkincsem
8

Here is your answer:

540

Explanation:

ΔV = ∫E. dr

ΔV = ∫(10r+5). dr

ΔV = [(10r^2/2+5r)]

( r varying from 1 to 10)

ΔV = [(10x10x10/2+5x10)] -[(10/2+5]

ΔV = [(500+50)] -[10]

ΔV = 540

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