Question

The magnitude of electric field intensity E is such that, an electron placed in it would experience an electrical force equal to its weight is given by
(a) mge
(b) mg/e
(c) e/mg
(d) e²g/m²

Answer 1

Given,

The magnitude of electric field intensity E such that an electron placed in it would experience an electrical force equal to its weight is given by .....

mass of electron is m, charge on each electron is e and acceleration due to gravity is g

a/c to question,

weight of electron = electrical force experienced by electron

⇒mass × acceleration due to gravity = charge × electric field intensity

⇒ mg = eE

⇒E = mg/e

therefore electric field intensity E is given by mg/e. option (b) is correct choice.

Answer 2

Answer:

weight of electron = electrical force experienced by electron

⇒mass × acceleration due to gravity = charge × electric field intensity

⇒ mg = eE

⇒E = mg/e