Question

The magnitude of electrostatic force between two particles separated by distance 1 cm and carrying charge 2 μC each, will be

360 N

240 N

120 N

36 N

Answer 1

Given:

2 particles carrying charge 2 μC , separated by 1 cm.

To find:

Magnitude of electrostatic force?

Calculation:

Let force be F :

$F = \dfrac{1}{4\pi \epsilon_{0}} \times \dfrac{ {q}^{2} }{ {d}^{2} }$

$\implies F =( 9 \times {10}^{9} ) \times \dfrac{ {(2 \times {10}^{ - 6}) }^{2} }{ {(0.01)}^{2} }$

$\implies F =( 9 \times {10}^{9} ) \times \dfrac{4 \times {10}^{ - 12} }{ {10}^{ - 4} }$

$\implies F =36 \times {10}^{9} \times {10}^{ - 8}$

$\implies F =36 \times10$

$\implies F =360 \: N$

So electrostatic force between the charges is 360 N.