Question

the magnitude of electrostatic force between two point charges, separated by a distance r is f. If the distance between the charges is doubled, then the new electrostatic force will be

•F/4
•F/2
•2F
•4F
​

Answer 1

Answer:

Correct option is

B

F

Step 1: Initial Force

Initially, the force between charges say q

1

and q

2

seperated with distance r is :

F=

4πϵ

0

1

r

2

q

1

q

2

Step 2: New force calculation

When the charge is doubled and the distance between charges is also doubled,

i.e q

1

′

=2q

1

,q

2

′

=2q

2

,r

′

=2r

The new force will be :

F

′

=

4πϵ

0

1

r

′2

q

1

′

q

2

′

F

′

=

4πϵ

0

1

(2r)

2

(2q

1

)(2q

2

)

=

4πϵ

0

1

r

2

q

1

q

2

=F

Hence, the force will remain the same.

Hence, Option(B) is correct.

Answer 2

Explanation:

so accordingly,

if distance doubled , force will be F/4.

option (a) is ur answrr.

hope u understand my difficulty.