Question

The magnitude of Force A=10N
B=20N angle=120 find the
Resultant?​

Answer 1

Answer:

$net \: force \: = \sqrt{ {10}^{2} + {20}^{2} + 2\times 10 \times 20 \times \cos(120) }$

$net \: force = \sqrt{ {10}^{2} + {20}^{2} +2\times 10 \times 20 \times ( - 0.5) }$

$net \: force \: = \sqrt{ {10}^{2} + {20}^{2} - 200} \\ net \: force \: = \sqrt{100 + 400 - 200} \\ net \: force = \sqrt{400} \\ net \: force = \sqrt{300}$

Net Force = 10√3 N

Answer 2

resultant is 10 root 3 N.

u can use the formula

resultant square = a ^ 2 + b^2 + 2abcos theta