The magnitude of force in CGS is 100dyne. let kilogram,metre, and minute are the fundamental units, then the magnitude of force will be?
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Bonjour!¡
The magnitude of force will be:
0.01N
saran2001:
how?, please send the calculations
let the value of force in another system where the fundamental physical quantities are kg,meter,minute be x
then ,using the formula : N1 U1=N2 U2,
the dimensional formula of force = MLT^(-2)
100dynes/x = (g/kg)*(cm/m)* [ (seconds/minute)^(-2) ]
hence,
100/x= (g/1000g)*(cm/100cm)* [(second/60seconds) ]^-2
100/x = 10^(-3)* 10^(-2)* 1/60*60 {since 1kg = 1000g,1 m=100cm,1minute=60 seconds and here 60*60 because of square of time in denominator
solving we get, x=3.6
then ,using the formula : N1 U1=N2 U2,
the dimensional formula of force = MLT^(-2)
100dynes/x = (g/kg)*(cm/m)* [ (seconds/minute)^(-2) ]
hence,
100/x= (g/1000g)*(cm/100cm)* [(second/60seconds) ]^-2
100/x = 10^(-3)* 10^(-2)* 1/60*60 {since 1kg = 1000g,1 m=100cm,1minute=60 seconds and here 60*60 because of square of time in denominator
solving we get, x=3.6
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